在Oracle SQL中启动和连接
发布时间:2021-03-31 12:36:50 所属栏目:站长百科 来源:网络整理
导读:我有桌子如下 帐户 CUSTOMER_ID PAYING_ACCOUNT_ID PARENT_ACCOUNT_ID ACCOUNT_ID COMPANY_ID 24669 24669 24669 24669 0 24671 24671 24669 24671 0 24670 24670 24669 24670 0 3385217 3385217 24670 3385217 0 158 158 158 158 0159 159 158 159 0160 160
我有桌子如下 帐户 CUSTOMER_ID PAYING_ACCOUNT_ID PARENT_ACCOUNT_ID ACCOUNT_ID COMPANY_ID 24669 24669 24669 24669 0 24671 24671 24669 24671 0 24670 24670 24669 24670 0 3385217 3385217 24670 3385217 0 158 158 158 158 0 159 159 158 159 0 160 160 159 160 0 161 161 160 161 0 162 162 160 162 0 180 180 180 180 0 这是DDL CREATE TABLE "SYSTEM"."ACCOUNT" ("CUSTOMER_ID" NUMBER(20,0) NOT NULL ENABLE,"PAYING_ACCOUNT_ID" NUMBER(20,0),"PARENT_ACCOUNT_ID" NUMBER(20,"ACCOUNT_ID" NUMBER,"COMPANY_ID" NUMBER) 这是我的查询 select lpad(' ',2*level) || A.ACCOUNT_ID AS LEVEL_LABEL,LEVEL,A.* from ACCOUNT A start with PARENT_ACCOUNT_ID IN (select PARENT_ACCOUNT_ID from ACCOUNT where ACCOUNT_ID IN (select PARENT_ACCOUNT_ID from ACCOUNT where parent_account_id != account_id) and ACCOUNT_ID = PARENT_ACCOUNT_ID) CONNECT BY NOCYCLE PRIOR A.ACCOUNT_ID = A.PARENT_ACCOUNT_ID; 查询的主要目的是选择具有层次关系的数据,即PARENT_ACCOUNT_ID& ACCOUNT_ID,但是我得到了查询返回的重复数据 任何建议都非常感谢.谢谢 解决方法为什么不简单:SELECT level,* FROM accounts START WITH parent_account_id = account_id CONNECT BY PRIOR account_id = parent_account_id AND account_id <> parent_account_id ? (编辑:威海站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |